Solution: In the word Examination, E, X, A, M, I, N, T, O there are 8 distinct words. Case I: All words are distinct We can take 4 words from 8 distinct in 8C4 and we can arrange the 4 words in 4! ways. Total number of ways=8C4 x 4! ways=1680 Case II:1 word is alike and 2 is distinct There are 3 groups of alike words .We can choose in 3C1 ways and the distinct words in 7C2 . We can arrange the words in 4! ways but two words are the same so 4! / 2! ways. Total number of ways=7C2 x 3C1 x 4!/2!=756 Case III:Two are alike Total number of ways: 3C2 x 4!/2! x 2!=18 Total of ways in which 4 letter words can be made out of the word EXAMINATION= 1680 +756 +18=2454 Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! |
